[Haskell-cafe] Re: Review request for my permutations implementation

[Daniel Fischer]

Am Donnerstag 07 Januar 2010 14:04:20 schrieb Maciej Piechotka:

>
> As pointed out perms [] = [[]]. You can note that:
> length . perms == factorial

Surely you meant

genericLength . perms == factorial . (genericLength :: [a] -> Integer)

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