[Haskell-cafe] How to "instance MonadIO Identity"?
Magicloud Magiclouds
magicloud.magiclouds at gmail.com
Tue Dec 28 06:29:05 CET 2010
Hi,
From another thread in this list, I got code as:
> instance MonadIO Identity where
> liftIO = id
Well, it does not work for me as:
Message.hs:22:12:
Couldn't match expected type `Identity a' with actual type `IO a'
Expected type: IO a -> Identity a
Actual type: IO a -> IO a
In the expression: id
In an equation for `liftIO': liftIO = id
--
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