[Haskell-cafe] how to write a loop in haskell way
Ivan Lazar Miljenovic
ivan.miljenovic at gmail.com
Sun Dec 19 11:49:47 CET 2010
On 19 December 2010 21:27, ender <crazyender at gmail.com> wrote:
> Hi all:
> I'v been learning haskell for several months, and now I'm trying
> to write some "real word" program in haskell, like finding files under
> one directory or something
> My problem is that, I dont know the way of writing a loop in
> haskell. I searched google and found some code that translate c loop
> into haskell like this one:
>
>> > > I am new to haskell and would look to write a function equivalent
>> > > to the following loop in C
>> > >
>> > > int value = 500000;
>> > > int part_stack[4];
>> > > int *part_ptr = part_stack;
>> > > for (; value; value /= 10000)
>> > > *part_ptr++ = value % 10000;
>> >
>> > part_stack :: [Int]
>> > part_stack = [0,50]
>> >
>> > Note that I've performed a memoization optimization--this
>> > makes the code both smaller, faster and easier to read! :P
>>
>> Ignore David, he's pulling your leg. Here's the proper translation:
>>
>> do
>> alloca $ \value -> do
>> poke value (500000::Int)
>> allocaArray 4 $ \part_stack -> do
>> alloca $ \part_ptr -> do
>> poke part_ptr part_stack
>> let loop = do
>> val <- peek value
>> if val == 0 then return () else do
>> p <- peek part_ptr
>> poke p (val `rem` 10000)
>> poke part_ptr (p `plusPtr` 1)
>> poke value (val `quot` 10000)
>> loop
>> loop
>
> and I really think that's not a "haskell way", it's just translate c
> code into haskell code byte by byte
> My question is: how to translate above c code into haskell in "haskell way"
Short answer: you don't.
Longer answer: have a read through
http://book.realworldhaskell.org/read/io-case-study-a-library-for-searching-the-filesystem.html
--
Ivan Lazar Miljenovic
Ivan.Miljenovic at gmail.com
IvanMiljenovic.wordpress.com
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