[Haskell-cafe] $ do?
geddes.jonathan at gmail.com
Wed Dec 15 03:59:14 CET 2010
Why do I need the $ in the following bits of code?
> main = withSocketsDo $ do
> --do something with sockets
> foo = fromMaybe 0 $ do
> --do something in the maybe monad
I don't see (after admittedly only a minute or so thinking about it)
where any grammar ambiguities would be if 'do' had an implicit $ in
front of it:
> foo = fromMaybe 0 do
> --do something in maybe
Though now that I've written it down, that is hard for me to visually
parse at a glance. I'm still curious though.
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