[Haskell-cafe] Can we come out of a monad?
Daniel Fischer
daniel.is.fischer at web.de
Mon Aug 9 15:49:10 EDT 2010
On Monday 09 August 2010 21:19:01, John Lato wrote:
>
> I don't find purify2 particularly helpful because I almost never want
> to break out of any arbitrary monad; I want to be able to break out of
> a specific monad without knowing which monad it is, that is:
>
> purify3 :: Monad m => m a -> a
> purify3 = undefined --the only possible definition...
Just to be obnoxious:
purify3 = const undefined
;)
>
> However, I just realized that something else is almost as good:
>
> evalCont :: Cont r a -> r
> evalCont k = runCont k id
Wouldn't you want the signature
Cont r a -> a
to break out? Also:
ContBreak.hs:6:23:
Couldn't match expected type `r' against inferred type `a'
`r' is a rigid type variable bound by
the type signature for `evalCont' at ContBreak.hs:5:17
`a' is a rigid type variable bound by
the type signature for `evalCont' at ContBreak.hs:5:19
In the second argument of `runCont', namely `id'
In the expression: runCont k id
In the definition of `evalCont': evalCont k = runCont k id
evalCont :: (forall r. Cont r a) -> a
evalCont k = runCont k id
would work (but is something different).
>
> As Cont is the "Mother of all monads", it can be used to emulate the
> behavior of any other monad. If you had a library with instances of
> MonadReader, MonadWriter, MonadState, etc. (or operational
> equivalents) defined for the Cont monad, then you would have a purify
> function that works for all interesting monads (except IO, STM, and
> maybe ST), which is almost as good.
>
> John
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