[Haskell-cafe] Re: instance Eq (a -> b)

[Ashley Yakeley]

On Wed, 2010-04-14 at 08:13 +0100, Thomas Davie wrote:
> Your instances of Finite are not quite right:
> 
> bottom :: a
> bottom = doSomethingToLoopInfinitely.
> 
> instance Finite () where
>  allValues = [(), bottom]

Bottom is not a value, it's failure to evaluate to a value.

But if one did start considering bottom to be a value, one would have to
distinguish different ones. For instance, (error "ABC") vs. (error
"PQR"). Obviously this is not finite.

-- 
Ashley Yakeley