[Haskell-cafe] instance Eq (a -> b)

[Jonas Almström Duregård]

I guess nontermination is a problem (e.g. if one or both functions
fail to terminate for some values, equality will be undecidable).

/Jonas

On 14 April 2010 08:42, Ashley Yakeley <ashley at semantic.org> wrote:
> On Wed, 2010-04-14 at 16:11 +1000, Ivan Miljenovic wrote:
>> but the only way you can "prove" it in
>> Haskell is by comparing the values for the entire domain  (which gets
>> computationally expensive)...
>
> It's not expensive if the domain is, for instance, Bool.
>
> --
> Ashley Yakeley
>
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