[Haskell-cafe] How to understand the 'forall' ?

[Bulat Ziganshin]

Hello Cristiano,

Wednesday, September 16, 2009, 12:04:48 PM, you wrote:

> Yep, perhaps I used the wrong example. What about foo: (forall a. a) -> Int?

it's a function that convert anything to integer. for example:

foo _ = 1

it's hard to find better examples, since haskell has very few
functions with fully polymorphic arguments


-- 
Best regards,
 Bulat                            mailto:Bulat.Ziganshin at gmail.com