[Haskell-cafe] list -> sublists

[Eduard Sergeev]

satorisanitarium wrote:
> 
> How to make a list of sublists out of a list, whether they be a list of
> numbers or a string.
> 

Without recursion (with fold) starting from the tail of the input list:

foo n = foldr st [[]]
    where
        st x xss | x == n = [x]:xss
        st x (xs:xss) = (x:xs):xss 
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