[Haskell-cafe] Re: Fair diagonals
apfelmus at quantentunnel.de
Wed Nov 4 09:56:28 EST 2009
Luke Palmer wrote:
> I believe you can get what you want using the diagonal function from
> product xs ys = [ [ (x,y) | y <- ys ] | x <- xs ]
> diag2 xs ys = diagonal (product xs ys)
> I think if you separate taking the cartesian product and flattening
> it, like this, you might have an easier time wrangling all the
> different variants you want.
Note that Control.Monad.Omega is not a monad. The law of associativity
is broken, at least in a direct sense.
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