[Haskell-cafe] Are all arrows functors?
porges at porg.es
Tue Nov 3 21:32:21 EST 2009
See also the paper "Idioms are oblivious, arrows are meticulous,
monads are promiscuous" . Functors can be extended to give
applicative functors (idioms) which can then be extended to arrows,
and then monads. So all arrows are also (applicative) functors.
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