[Haskell-cafe] About the lazy pattern
batterseapower at hotmail.com
Thu May 28 07:35:16 EDT 2009
2009/5/28 Petr Pudlak <deb at pudlak.name>:
> Hi Ryan, thanks for a nice and thorough explanation. I had trouble
> understanding the section of the tutorial as well. Maybe it would deserve to
> rewrite to something a bit simpler?
> Anyhow, I'd like to ask: Is there a reason for which pattern matching for
> single-constructor data types isn't lazy by default? For example, why do I have
> to write
>> weird ~(x,y) = (1,x)
>> crazy = weird crazy
> when the compiler knows that the type (x,y) has just the single constructor,
> and could automatically introduce the additional laziness without any risk?
I think this is really two questions:
1) Why can't the /compiler/ add extra laziness automatically?
Because it's not semantics preserving:
weird (x, y) = (1, x)
lazyWeird ~(x, y) = (1, x)
weird undefined = undefined
lazyWeird undefined = (1, undefined)
Of course, it's arguable as to whether turning non-terminating
programs into terminating ones is really that big of a deal. In fact,
some transformations in GHC already make this kind of change for
optimization purposes (albeit only to things of function type, where
the waters are murkier).
Even if it were semantics preserving, making things MORE lazy is not
likely to lead to performance improvement, so I doubt the compiler
would want to do this.
2) Why isn't product pattern matching lazy by default in Haskell?
I can't give a definitive answer, but I suspect that the reason is
that the Haskell design team didn't want adding an extra constructor
to your type definition to change the semantics of all the pattern
matches in your program. Seems pretty sensible to me :-)
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