[Haskell-cafe] Just 3 >>= (1+)?
daniel.is.fischer at web.de
Sat May 9 17:03:32 EDT 2009
Am Samstag 09 Mai 2009 21:31:20 schrieb michael rice:
> Why doesn't this work?
> [michael at localhost ~]$ ghci
> GHCi, version 6.10.1: http://www.haskell.org/ghc/ :? for help
> Loading package ghc-prim ... linking ... done.
> Loading package integer ... linking ... done.
> Loading package base ... linking ... done.
> Prelude> Just 3 >>= (1+)
> No instance for (Num (Maybe b))
> arising from a use of `it' at <interactive>:1:0-14
> Possible fix: add an instance declaration for (Num (Maybe b))
> In the first argument of `print', namely `it'
> In a stmt of a 'do' expression: print it
The type of (>>=) is Monad m => m a -> (a -> m b) -> m b,
the type of (1 +) is Num n => n -> n.
Using (1 +) as the second argument of (>>=), you must unify
Num n => n -> n
Monad m => a -> m b
the types of the arguments and results must match, so
a = n
m b = n = a
, giving the type
(Monad m, Num (m b)) => m b -> m b
The first argument of (>>=) is Just 3 :: Num k => Maybe k.
That must be unified with m a, giving m = Maybe and a = k. On the other hand we previously
found a = m b, so in
Just 3 >>= (1 +)
the (1 +) has type
Num (Maybe b) => Maybe b -> Maybe b
and Just 3 has type
Num (Maybe b) => Maybe (Maybe b).
But ghci can't find an instance Num (Maybe b).
You probably wanted
fmap (1 +) (Just 3)
~> Just 4
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