[Haskell-cafe] Unfold fusion

[Martin Huschenbett]

Adrian Neumann schrieb:
> Hello,
> 
> I'm trying to prove the unfold fusion law, as given in the chapter 
> "Origami Programming" in "The Fun of Programming". unfold is defined 
> like this:
> 
> unfold p f g b = if p b then [] else (f b):unfold p f g (g b)
> 
> And the law states:
> 
> unfold p f g . h = unfold p' f' g'
> with
>     p' = p.h
>     f' = f.h
>     h.g' = g.h
> 
> Foremost I don't really see why one would want to fuse h into the 
> unfold. h is executed once, at the beginning and is never needed again. 
> Can someone give me an example?

Maybe you should read the euqation from the other direction. Then the h 
becomes "fused out" and is called only once instead of many times. But 
you can only do this if you can factor out h from p', f' and g'.

> So, this is what I got so far:
> 
> unfold p f g.h = (\b -> if p b then [] else (f b): unfold p f g (g b).h
> = if p (h b) then [] else (f (h b)) : unfold p f g (g (h b))
> = if p' b then [] else f' b: unfold p f g (h (g' b))
> 
> not very much. I kinda see why it works after I "unfold" some more, but 
> I can't really prove it. I suspect I need some technique I haven't 
> learned yet. I've heard about fixpoint induction, that looks promising, 
> but Google knows very little about it.
> 
> I hope somebody can give me some hints.
> 
> Regards,
> 
> Adrian

Regards,

Martin.

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