[Haskell-cafe] Rational and % operator remix

[michael rice]

Hi,

Thanks again for the help last night.

The second function cf2 is an attempt to reverse the process of the first function, i.e., given a rational number it returns a list of integers, possibly infinite, but you shouldn't get into trouble if you use 98%67 as input (output should be [1,2,6,5]). The interpreter is complaining about the '=' following the 'in' keyword. Is there a better way to state this?

Michael

import Data.Ratio
cf :: [Int] -> Rational
cf (x:[]) = toRational x
cf (x:xs) = toRational x + 1 / cf xs

cf2 :: Rational -> [Int]
cf2 a = let ai = toRational (floor ((numerator a) / (denominator a)))
            in
              if a = ai
                then [a]
                else ai : cf2 ((toRational 1) / (subtract ai a))




      
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