[Haskell-cafe] bytestring vs. uvector
manlio_perillo at libero.it
Fri Mar 13 10:04:45 EDT 2009
Don Stewart ha scritto:
>> I think uvector only works with certain types that can be
>> unboxed, while storablevector works with all types that
>> instantiate Foreign.Storable.Storable. I don't know about
>> vector. From the description of vector, I have the
One of the nice feature of uvector is the support for UArr (a :*: b).
An UArr (a :*: b) can be easily (with fstU and sndU) transformed in
UArr a and UArr b.
uvector package also suppors Complex and Rational, however the support
for these type is "hard written", using a UAProd class, and requires
some boiler plate code (IMHO).
I find StorableVector implementation much more simple; I would like to
see it in the Haskell Platform.
As for Data.Parallel, uvector and vector, it seems there is some code
Both Data.Parallel and uvector, make us of a strict pair type.
Such a type is also implemented in the strict package .
The authors are the same, so I don't understand the reason of code
There is also replication in the definition of the Stream data type.
 there seems to be an error in the documentation:
In the description, there is:
"Same as regular Haskell pairs, but (x :*: _|_) = (_|_ :*: y) = _|_"
but in the synopsis, the data constructor is :!:, not :*:.
Regards Manlio Perillo
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