[Haskell-cafe] Pattern matching does not work like this?
sebf at informatik.uni-kiel.de
Thu Jul 16 03:21:10 EDT 2009
On Jul 15, 2009, at 2:30 PM, Hans Aberg wrote:
>> If ++ could be pattern matched, what should have been the result of
>> "let (x++y)=[1,2,3] in (x,y)"?
>> It will branch. In terms of unification, you get a list of
>> f :: [a] -> ([a],[a])
>> f (x ++ y) = (x,y)
> For an argument s, any pair (x, y) satisfying s = x ++ y will match.
> That is, if s = [s_1, ..., s_k], the solutions j = 0, ..., k, x =
> [s_1, ..., s_j], y = [s_(j+1), ..., s_k]. And for each one, a
> potentially different value could given. That is, s could produce
> multiple values.
Curry (a Haskell extension with non-determinism) supports exactly that.
Sergio Antoy and Michael Hanus: Declarative Programming with Function
available at: <http://www.informatik.uni-kiel.de/~mh/papers/
Underestimating the novelty of the future is a time-honored tradition.
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