[Haskell-cafe] Re: AW: Example for formatted show in HStringTemplate

[John MacFarlane]

Torsten,

I'm not quite sure what you're asking -- but this simple example seems
to work fine:

Prelude Text.StringTemplate> let (a :: StringTemplate String) = newSTMP "$day;format=\"%d.%b.%Y\"$"
Prelude Text.StringTemplate Data.Time> render $ setAttribute "day" (ModifiedJulianDay 234) a
"09.Jul.1859"

John

+++ Kemps-Benedix Torsten [Jul 14 09 12:20 ]:
> John,
> 
> thanks for your answer, but HStringtemplate has instance definitions for Date.Time.Day. The question is more on the script side: How do I have to write the ST calls with ";format=" embedded in HTML?
> 
> regards,
> 
> Torsten 
> 
> 
> 
> -----Ursprüngliche Nachricht-----
> Von: John MacFarlane [mailto:fiddlosopher at gmail.com] 
> Gesendet: Dienstag, 14. Juli 2009 08:20
> An: Kemps-Benedix Torsten
> Cc: HAppS at googlegroups.com; haskell-cafe at haskell.org
> Betreff: Re: Example for formatted show in HStringTemplate
> 
> +++ Kemps-Benedix Torsten [Jul 13 09 23:56 ]:
> > Hello,
> > 
> > is there a working example of how to use the format clause with HStringTemplate, e.g. for Data.Time.Day? I think, if there is a parameter $day$, a reasonable template might contain e.g.:
> > 
> > $day;format="%d.%b.%Y"$
> > 
> > But I only get "toModifiedJulianDay: [54960]" as the result which corresponds to the unformatted show.
> 
> You probably need to define a StringTemplateShows instance for
> Data.Time.Day, and then use stShowsToSE to define a ToSElem instance.
> Something like
> 
> instance StringTemplateShows Day
>   where stringTemplateFormattedShow formatString = formatTime defaultTimeLocale formatString 
>    {- or whatever -- I'm not sure what the correct time-formatting function is -}
> 
> instance ToSElem Day
>   where toSElem = stShowsToSE
> 
> John
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