[Haskell-cafe] ANNOUNCE: pqueue-mtl, stateful-mtl
Louis Wasserman
wasserman.louis at gmail.com
Thu Feb 19 17:14:34 EST 2009
Ryan, I didn't get your question after the first read, so here's an actual
answer to it --
What I want to preserve about ST is the existence of a guaranteed safe
runST, really. I tend to do algorithms and data structures development,
which almost never requires use of IO, or references of any kind -- usually
STArrays for intermediate computations are what I'm actually interested in,
and the actual outputs of my code are generally not monadic at all.
But I see how it would be useful in general. I'll add it in.
Louis Wasserman
wasserman.louis at gmail.com
On Thu, Feb 19, 2009 at 2:51 PM, Louis Wasserman
<wasserman.louis at gmail.com>wrote:
> Oh, sweet beans. I hadn't planned to incorporate mutable references -- my
> code uses them highly infrequently -- but I suppose that since mutable
> references are really equivalent to single-threadedness where referential
> transparency is concerned, that could be pulled off -- I would still want a
> StateThread associated type, but that'd just be RealWorld for IO and STM, I
> guess.
>
> Louis Wasserman
> wasserman.louis at gmail.com
>
>
> On Thu, Feb 19, 2009 at 2:40 PM, Ryan Ingram <ryani.spam at gmail.com> wrote:
>
>> So, why not use this definition? Is there something special about ST
>> you are trying to preserve?
>>
>> -- minimal complete definition:
>> -- Ref, newRef, and either modifyRef or both readRef and writeRef.
>> class Monad m => MonadRef m where
>> type Ref m :: * -> *
>> newRef :: a -> m (Ref m a)
>> readRef :: Ref m a -> m a
>> writeRef :: Ref m a -> a -> m ()
>> modifyRef :: Ref m a -> (a -> a) -> m a -- returns old value
>>
>> readRef r = modifyRef r id
>> writeRef r a = modifyRef r (const a) >> return ()
>> modifyRef r f = do
>> a <- readRef r
>> writeRef r (f a)
>> return a
>>
>> instance MonadRef (ST s) where
>> type Ref (ST s) = STRef s
>> newRef = newSTRef
>> readRef = readSTRef
>> writeRef = writeSTRef
>>
>> instance MonadRef IO where
>> type Ref IO = IORef
>> newRef = newIORef
>> readRef = readIORef
>> writeRef = writeIORef
>>
>> instance MonadRef STM where
>> type Ref STM = TVar
>> newRef = newTVar
>> readRef = readTVar
>> writeRef = writeTVar
>>
>> Then you get to lift all of the above into a monad transformer stack,
>> MTL-style:
>>
>> instance MonadRef m => MonadRef (StateT s m) where
>> type Ref (StateT s m) = Ref m
>> newRef = lift . newRef
>> readRef = lift . readRef
>> writeRef r = lift . writeRef r
>>
>> and so on, and the mention of the state thread type in your code is
>> just gone, hidden inside Ref m. It's still there in the type of the
>> monad; you can't avoid that:
>>
>> newtype MyMonad s a = MyMonad { runMyMonad :: StateT Int (ST s) a }
>> deriving (Monad, MonadState, MonadRef)
>>
>> But code that relies on MonadRef runs just as happily in STM, or IO,
>> as it does in ST.
>>
>> -- ryan
>>
>> 2009/2/19 Louis Wasserman <wasserman.louis at gmail.com>:
>> > It does. In the most recent version, the full class declaration runs
>> >
>> > class MonadST m where
>> > type StateThread m
>> > liftST :: ST (StateThread m) a -> m a
>> >
>> > and the StateThread propagates accordingly.
>> >
>> > Louis Wasserman
>> > wasserman.louis at gmail.com
>> >
>> >
>> > On Thu, Feb 19, 2009 at 2:10 AM, Sittampalam, Ganesh
>> > <ganesh.sittampalam at credit-suisse.com> wrote:
>> >>
>> >> Henning Thielemann wrote:
>> >> > On Mon, 16 Feb 2009, Louis Wasserman wrote:
>> >> >
>> >> >> Overnight I had the following thought, which I think could work
>> >> >> rather well. The most basic implementation of the idea is as
>> >> >> follows:
>> >> >>
>> >> >> class MonadST s m | m -> s where
>> >> >> liftST :: ST s a -> m a
>> >> >>
>> >> >> instance MonadST s (ST s) where ...
>> >> >> instance MonadST s m => MonadST ...
>> >> >
>> >> > Like MonadIO, isn't it?
>> >>
>> >> I think it should be, except that you need to track 's' somewhere.
>> >>
>> >> Ganesh
>> >>
>> >>
>> >>
>> ==============================================================================
>> >> Please access the attached hyperlink for an important electronic
>> >> communications disclaimer:
>> >>
>> >> http://www.credit-suisse.com/legal/en/disclaimer_email_ib.html
>> >>
>> >>
>> ==============================================================================
>> >>
>> >
>> >
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>>
>
>
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