[Haskell-cafe] Re: Overloading functions based on arguments?

[minh thu]

Why do you say "every name and operator" ? Why do you say "fully qualified" ?
When there is some clash, hiding the offending name or importing
"qualified as" is
quite satisfying imho.

Thu

2009/2/13 John A. De Goes <john at n-brain.net>:
>
> The signal-to-noise ratio with fully qualified names/operators goes way down
> -- that's the need.
>
> Go take one of your programs and fully qualify every name and every
> operator. Doesn't look so pretty then, does it? And it wouldn't be easy to
> read, either.
>
> Regards,
>
> John A. De Goes
> N-BRAIN, Inc.
> The Evolution of Collaboration
>
> http://www.n-brain.net    |    877-376-2724 x 101
>
> On Feb 13, 2009, at 9:37 AM, Henning Thielemann wrote:
>
>>
>> On Fri, 13 Feb 2009, John A. De Goes wrote:
>>
>>> In any case, no one has really addressed the original poster's question:
>>> No, "name overloading" is not possible in Haskell, and surprisingly, there
>>> are no blocking technical issues why this must be the case.
>>
>> Prefixing names with module names is good style:
>>  http://www.haskell.org/haskellwiki/Qualified_names
>> Where is the need for more overloading?
>>
>
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