[Haskell-cafe] Re: Complex C99 type in Foreign

[Maurí­cio]

>>>> Are there plans to include C99 'complex' type
>>>> in Foreign, maybe as CFloatComplex, CDoubleComplex

>>> A separate library for new types to add to Foreign would be the easiest
>>> way forward. Just put the foreign-c99 package on Hackage?

>> (...) I could actually have some
>> arbitrary sized parameter as argument to a function
>> or as a return value (and not its pointer), what
>> did I saw wrong? I understand only Foreign.C.C*
>> types or forall a. => Foreign.Ptr.Ptr a can be used
>> like that.
> 
> Oh, you mean you need to teach the compiler about unboxed complex types?
> 

I'm sorry, maybe I didn't understand you well. Are
you saying that I could get this 'CComplex' type using
unboxed types and other things already available?

Maurício