[Haskell-cafe] Haskell and "memoization"

[Daniel Peebles]

It does compute the result of a function application more than once if you
ask for it more than once, and that's why we need memoization.

Dan

On Tue, Dec 15, 2009 at 10:32 PM, michael rice <nowgate at yahoo.com> wrote:

> I'm looking here at the Fibonacci stuff:
>
> http://www.haskell.org/haskellwiki/Memoization
>
> Since (I've read) Haskell never computes the value
> of a function more than once, I don't understand the
> need for memoization.
>
> Enlighten me.
>
> Michael
>
>
>
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