[Haskell-cafe] gbp sign showing as unknown character by GHC
Iain Barnett
iainspeed at gmail.com
Thu Aug 20 07:39:11 EDT 2009
2009/8/20 Ketil Malde <ketil at malde.org>
>
> Stuart Cook <scook0 at gmail.com> writes:
>
> > GHCi, version 6.8.2: http://www.haskell.org/ghc/ :? for help
> > Loading package base ... linking ... done.
> > Prelude> map Data.Char.ord "饁"
> > [39233] <== 0x9941
> > Prelude> putStrLn "饁"
> > A <== 0x41
>
> > It seems that GHCi is clever enough to decode UTF-8 input, which only
> > serves to confuse System.IO even more.
>
> I get:
>
> GHCi, version 6.8.2: http://www.haskell.org/ghc/ :? for help
> Loading package base ... linking ... done.
> Prelude> map Data.Char.ord "饁"
> [39233]
>
> and
>
> Prelude> map Data.Char.ord "£"
> [163]
>
> but also:
>
> % ghci -e 'map Data.Char.ord "饁"'
> <interactive>:1:21:
> lexical error in string/character literal at character '\129'
>
> but again:
>
> % ghci -e 'map Data.Char.ord "£"'
> [194,163]
>
> So GHCi used interactively translates input from the terminal's UTF-8,
> but outputs truncates output to eight bits. Executing a string with
> -e, it appears to read byte for byte (which I think was the original
> behavior at some point).
>
> -k
> --
I get the same behaviour here.
If you want to try Latin 1 (ISO-8859-1) then you can use a utility called
Luit (maybe only Linux?)
luit -encoding ISO-8859-1 ghci
£ becomes £, but gives the same byte output as above.
Iain
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