[Haskell-cafe] Functor and Haskell
Kim-Ee Yeoh
a.biurvOir4 at asuhan.com
Thu Apr 23 01:28:24 EDT 2009
Daryoush Mehrtash-2 wrote:
>
>> singleton :: a -> [a]
>> singleton x = [x]
>>
>> Here F is the identity functor, and G is the list functor. And yes, C=D=
>> category of (a subset of) Haskell types.
>
> Are you saying the function that goes from list functor to singleton
> funtor
> is a natural transformation?
>
Here *singleton* is the natural transformation from the identity functor
to the list functor.
Daryoush Mehrtash-2 wrote:
>
> But aren't they functors to different subset of Haskell Types?
>
They're usually treated as endofunctors on Hask, for reasons
Ross Paterson has given.
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