[Haskell-cafe] Overriding a Prelude function?

[Ross Mellgren]

I think

import Prelude hiding ((>>))

does that.

-Ross

On Apr 22, 2009, at 11:44 AM, michael rice wrote:

> I've been working through this example from: http://en.wikibooks.org/wiki/Haskell/Understanding_monads
>
> I understand what they're doing all the way up to the definition of  
> (>>), which duplicates Prelude function (>>). To continue following  
> the example, I need to know how to override the Prelude (>>) with  
> the (>>) definition in my file rand.hs.
>
> Michael
>
> ==============
>
> [michael at localhost ~]$ cat rand.hs
> import System.Random
>
> type Seed = Int
>
> randomNext :: Seed -> Seed
> randomNext rand = if newRand > 0 then newRand else newRand +  
> 2147483647
>     where newRand = 16807 * lo - 2836 * hi
>           (hi,lo) = rand `divMod` 127773
>
> toDieRoll :: Seed -> Int
> toDieRoll seed = (seed `mod` 6) + 1
>
> rollDie :: Seed -> (Int, Seed)
> rollDie seed = ((seed `mod` 6) + 1, randomNext seed)
>
> sumTwoDice :: Seed -> (Int, Seed)
> sumTwoDice seed0 =
>   let (die1, seed1) = rollDie seed0
>       (die2, seed2) = rollDie seed1
>   in (die1 + die2, seed2)
>
> (>>) m n = \seed0 ->
>   let (result1, seed1) = m seed0
>       (result2, seed2) = n seed1
>   in (result2, seed2)
>
> [michael at localhost ~]$
>
>
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