[Haskell-cafe] Stacking monads

Ryan Ingram ryani.spam at gmail.com
Fri Oct 3 15:48:28 EDT 2008

On Fri, Oct 3, 2008 at 12:43 PM, Andrew Coppin
<andrewcoppin at btinternet.com> wrote:
>  factorise n = do
>   x <- [1..]
>   y <- [1..]
>   if x*y == n then return (x,y) else fail "not factors"
> This is a very stupid way to factorise an integer. (But it's also very
> general...) As you may already be aware, this fails miserably because it
> tries all possible values for y before trying even one new value for x. And
> since both lists there are infinite, this causes an endless loop that
> produces (almost) nothing.

You should look at LogicT at http://okmij.org/ftp/Computation/monads.html

The magic words you are looking for are "fair disjunction" and "fair

The paper is full of mind-stretching code but it already does
everything you want.  And it is a monad transformer already, so it's
easy to attach Error to it.

  -- ryan

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