[Haskell-cafe] Exception handling when using STUArray
donn at avvanta.com
Wed Mar 12 18:45:27 EDT 2008
On Mar 12, 2008, at 2:10 PM, Henning Thielemann wrote:
> On Wed, 12 Mar 2008, Donn Cave wrote:
>> On Mar 12, 2008, at 12:32 PM, Brandon S. Allbery KF8NH wrote:
>>> On Mar 12, 2008, at 14:17 , Donn Cave wrote:
>>>> Sure. It isn't a lot of code, so I subjected it to Either-ization
>>>> as an experiment, and I did indeed take the monad procedural route.
>>> Monad != procedural, unless you insist on do notation. Think of
>>> it as composition (it may be easier to use (=<<) which "points
>>> the same direction" as (.)).
>> Yes, I insist on do notation, because it provides a convenient
>> binding form that works with what I'm doing - the original functional
>> variation wasn't so suited to composition either, and used `let'.
>> But I see that as only syntactic - equally procedural, either way.
>> Expressions are evaluated in a fixed order,
> Do notation only looks like there are statements that are processed
> from the beginning to the end. But that's not true, it's still
> purely lazy and expressions are evaluated in the order that is
> forced by data dependencies.
Let me put it this way: if I write
(i, s') <- decodeInt s
(v, _) <- decodeInt s'
return (i, v)
... instead of, to just avoid the monad stuff
case (decodeInt s) of
Left e -> Left e
Right (i, s') -> case (decodeInt s') of
Left e -> Left e
Right (v, _) -> Right (i, v)
... the `do' notation just emphasizes the procedural-ness of
this computation. I can't arrive at the end, without
completing these steps, whatever notation I choose. `do'
just happens to be considerably more convenient.
Of course data dependencies force the order of evaluation,
but some of those dependencies are inevitably built into
the expression: I can't evaluate the result (Right (i, _))
without evaluating the second decodeInt far enough to know
that it isn't (Left _). The type that we'd need for that
would be something like Either String (Int, (Either String Int))
(etc. ad nauseum as the return value gets more complex.)
Well, the problem inherently requires a certain order of
evaluation. But if you will just handle pattern match failure
in the IO monad, then you can write a simple functional
expression of the problem instead,
let (i, s') = decodeInt s in
let (v, _) = decodeInt s' in
... where I think `i' can be evaluated without forcing unnecessary
evaluation of v. It's clearer, and avoids unnecessary strictness!
Donn Cave, donn at avvanta.com
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