On 3/12/08, Neil Mitchell <ndmitchell at gmail.com> wrote:
> However, I don't believe this expression is type safe in Haskell.
Using higher-order polymorphism:
f (x :: forall a. a -> a) = x x
--
Taral <taralx at gmail.com>
"Please let me know if there's any further trouble I can give you."
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