[Haskell-cafe] automatically deriving Map and Filter on datatypes
etc.
Miguel Mitrofanov
miguelimo38 at yandex.ru
Thu Jun 5 04:28:02 EDT 2008
Well, it's certainly not possible for "filter", at least, not without
additional hints to the compiler. For example, consider this type:
data Weird a = A | B a (Weird a) (Weird a)
filter p A = A
filter p (B x w1 w2) | p x = B x (filter p w1) (filter p w2)
| otherwise = ?????
On 5 Jun 2008, at 12:03, Cetin Sert wrote:
> Hi ^_^,
>
> Let's say we have the following data type and functions:
> data Tab a = (:↺:)
>
> | a :↓: Tab a
> | Tab a :↙↘: (Tab a,Tab a)
> deriving (Eq, Show, Read)
>
> map f (:↺:) = (:↺:)
> map f (a :↓: t) = f a :↓: map f t
> map f (h :↙↘: (l,r)) = map f h :↙↘: (map f l, map f r)
>
>
> filter p (:↺:) = (:↺:)
> filter p (a :↓: t) | p a = filter p t
> | otherwise = a :↓: filter p t
> filter p (h :↙↘: (l,r)) = filter p h :↙↘: (filter p l, filter
> p r)
>
> is it possible to automatically derive map and filter?
> data Tab a = (:↺:)
> | a :↓: Tab a
> | Tab a :↙↘: (Tab a,Tab a)
> deriving (Eq, Show, Read, Map, Filter)
>
> If not, do you think it might be nice to have something like this in
> the future?
>
> Best Regards,
> Cetin Sert
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