[Haskell-cafe] 0/0 > 1 == False
cristi at ot.onrc.ro
Thu Jan 10 03:45:58 EST 2008
On Thu, 10 Jan 2008 10:22:03 +0200, Mitar <mmitar at gmail.com> wrote:
> Why is 0/0 (which is NaN) > 1 == False and at the same time 0/0 < 1 ==
> False. This means that 0/0 == 1? No, because also 0/0 == 1 == False.
> I understand that proper mathematical behavior would be that as 0/0 is
> mathematically undefined that 0/0 cannot be even compared to 1.
> There is probably an implementation reason behind it, but do we really
> want such "hidden" behavior? Would not it be better to throw some kind
> of an error?
I think it's a bug.
Here is why:
let f = (\x -> x/0) in f 0 == f 0
Referential transparency say that f 0 must equal to f 0, but in this case
it is not. :-)
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