[Haskell-cafe] Origins of '$'

Hans Aberg haberg at math.su.se
Tue Dec 9 16:38:24 EST 2008

On 8 Dec 2008, at 23:15, Joachim Breitner wrote:

> Am Montag, den 08.12.2008, 15:59 -0600 schrieb Nathan Bloomfield:
>> Slightly off topic, but the A^B notation for hom-sets also makes the
>> natural isomorphism we call currying expressable as A^(BxC) = (A^B) 
>> ^C.
> So A^(B+C) = A^B × A^C ?
> Oh, right, I guess that’s actually true:...

I posted some of those relations for lambda-calculus two days ago  
(this thread).

It is so very off-topic, because one can reverse the process, take  
those operators and some relations, and show it contains the lambda- 
calculus (or so I remember, don't recall details). Then one problem  
is that these operators are not so intuitive for all practical purposes.


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