[Haskell-cafe] Syntax of 'do'
dmhouse at gmail.com
Fri Aug 29 11:50:04 EDT 2008
2008/8/29 Philip Weaver <philip.weaver at gmail.com>:
> It sounds like you tried to redefine (>>) and (>>=) and make 'do' use the
> new definitions. This is not possible, regardless of what types you give
> (>>) and (>>=).
Watch out for rebindable syntax:
At first reading, I thought that -XNoImplicitPrelude was required to
turn this on. But now I'm not sure: it seems that if you hide
Prelude.>>= and Prelude.return, that ought to be enough to make do
notation work with your alternative definitions. I'm not at home, so I
can't try this right now.
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