[Haskell-cafe] The range operator
prstanley at ntlworld.com
Mon Apr 7 08:07:54 EDT 2008
At 12:28 07/04/2008, you wrote:
>On Fri, Apr 4, 2008 at 10:49 PM, Andrew Coppin
><andrewcoppin at btinternet.com> wrote:
> > More to the point, the range y..z goes in steps of y-z. ;-)
>[x,y..z] goes in steps of y-x ;-), [y..z] goes in steps of 1
>(depending on the type).
Could you elaborate please?
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