[Haskell-cafe] Rewriting filter with foldr

[PR Stanley]

The question is asking for a new definition of filter using foldr. 
Sorry, I should have mentioned that before.
Cheers, Paul
At 14:26 30/09/2007, you wrote:
>Perhaps a list comprehension better shows the intention of the 
>filter function:
>
>filter p xs = [x | x <- xs, p x]
>
>You can literally read that as "take all x from xs that satisfy p".