[Haskell-cafe] Rewriting filter with foldr

PR Stanley prstanley at ntlworld.com
Sun Sep 30 09:52:22 EDT 2007

The question is asking for a new definition of filter using foldr. 
Sorry, I should have mentioned that before.
Cheers, Paul
At 14:26 30/09/2007, you wrote:
>Perhaps a list comprehension better shows the intention of the 
>filter function:
>filter p xs = [x | x <- xs, p x]
>You can literally read that as "take all x from xs that satisfy p".

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