[Haskell-cafe] length defined with foldr
Brandon S. Allbery KF8NH
allbery at ece.cmu.edu
Wed Sep 19 23:22:15 EDT 2007
On Sep 19, 2007, at 23:17 , PR Stanley wrote:
> length = foldr (. n . 1 + n) 0
> Any idea how to define length with foldr. The above definition
> doesn't make much sense.
Still fighting with the botched OCR?
length = foldr (\_ n -> 1 + n) 0
brandon s. allbery [solaris,freebsd,perl,pugs,haskell] allbery at kf8nh.com
system administrator [openafs,heimdal,too many hats] allbery at ece.cmu.edu
electrical and computer engineering, carnegie mellon university KF8NH
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