[Haskell-cafe] length defined with foldr

[Stefan O'Rear]

On Thu, Sep 20, 2007 at 04:17:54AM +0100, PR Stanley wrote:
> Hi
> length = foldr (. n . 1 + n) 0
> Any idea how to define length with foldr. The above definition doesn't make 
> much sense.
> Many thanks, Paul

length = foldr (λ_ n → 1 + n) 0

or, in ASCII concrete syntax

length = foldr (\_ n -> 1 + n) 0

Stefan
-------------- next part --------------
A non-text attachment was scrubbed...
Name: not available
Type: application/pgp-signature
Size: 189 bytes
Desc: Digital signature
Url : http://www.haskell.org/pipermail/haskell-cafe/attachments/20070919/969204cb/attachment-0001.bin