[Haskell-cafe] Missing Symbol (2)

[Thomas Hartman]

as provided, this won't compile because v hasn't been defined.

f [] = 0
f (x:xs) = x . f xs

compiles but gives 

f :: (Num (a -> c)) => [c -> c] -> a -> c

which seems wrong. maybe I'm not understanding what v is not supposed to 
be.

I am thinking maybe you want iterate

*Main> take 5 $ iterate (+1) 0
[0,1,2,3,4]

It would be easier to understand your desired function if you would 
provide an example of desired usage.

t.




PR Stanley <prstanley at ntlworld.com> 
Sent by: haskell-cafe-bounces at haskell.org
09/19/2007 02:17 AM

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[Haskell-cafe] Missing Symbol (2)






Hi
Here's another one:
f [] = v
f (x:xs) = x . f xs
The "." is supposed to denote a generic operator - f [] maps to some 
value v and applied to non-empty list applies head to ? operator.
Thanks, Paul

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