[Haskell-cafe] turning an imperative loop to Haskell
lemming at henning-thielemann.de
Thu Sep 6 11:15:01 EDT 2007
On Thu, 6 Sep 2007, Axel Gerstenberger wrote:
> Thanks to all of you. The suggestions work like a charm. Very nice.
> I still need to digest the advices, but have already one further question:
> How would I compute the new value based on the 2 (or even more) last values
> instead of only the last one?
> [ 2, 3 , f 3 2, f((f 3 2) 3), f ( f((f 3 2) 3) f 3 2)), ...]
> (background: I am doing explicit time stepping for some physical problem,
> where higher order time integration schemes are interesting. You advance in
> time by extrapolating based on the old time step values.)
You might be interested in some ideas on how to solve differential
equations numerically in an elegant way:
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