[Haskell-cafe] The C Equiv of != in Haskell

[Tomasz Zielonka]

On Tue, May 29, 2007 at 11:20:27AM +0100, David House wrote:
> On 29/05/07, Daniel McAllansmith <dm.maillists at gmail.com> wrote:
> >Just in case there was some sort of miscommunication, the actual answer to
> >your question is (/=) :: a -> a -> Bool, as Neil said.
> 
> Almost, (/=) :: Eq a => a -> a.

Almost again!

(/=) :: Eq a => a -> a -> Bool

Best regards
Tomek