[Haskell-cafe] The C Equiv of != in Haskell

David House dmhouse at gmail.com
Tue May 29 06:20:27 EDT 2007


On 29/05/07, Daniel McAllansmith <dm.maillists at gmail.com> wrote:
> Just in case there was some sort of miscommunication, the actual answer to
> your question is (/=) :: a -> a -> Bool, as Neil said.

Almost, (/=) :: Eq a => a -> a.

(Just for completeness.)

-- 
-David House, dmhouse at gmail.com


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