[Haskell-cafe] Hi I need help for very simple question!

ivan gomez kguento at gmail.com
Fri Mar 2 13:04:17 EST 2007

Well, your function only remove space chars at  string beginning. You may
use  Prelude.words  ::  String -> [String] or  some as:

intoWords s = aux s []

2007/3/2, iliali16 <iliali16 at gmail.com>:
> Hi Haskell People,
> I have problem implementing one function. I think my idea is write but I
> have minor mistakes which I cannot get right since I progrem Haskell from
> very recently. No the function is called intoWords and has to take a
> string
> of any size and kind of characters.No I have to produce as output a list
> of
> strings.To have a rule which defines an element from the list is the space
> character which can also be included in the string.So what i think should
> be
> smth like. intoWord Hello my name is Smart should produse a list looking
> like [Hello,my,name,is,Smart] Now I tried to do it recucively to take the
> string and checks if an element is white space in the list using the
> isSPace
> build in function. This is my code please help me if you have any
> suggestions. Also I don't know how to produce a base case for my
> recursion.
> import Char
> intoWords ::String -> [String]
> intoWords  (x:xs)
>         |isSpace x = intoWords xs
>         |otherwise = xs
> Thanks in advance for any suggestions. I really want to understand this
> bloody function couse I've been tring for a week now and I have tried so
> many ways to produce it that now I am fed up with it and I want to know
> how
> should it work since I am curious now.
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