[Haskell-cafe] How to devide matrix into small blocks

[L.Guo]

Hi all:

I already have one matrix of type [[a]] to store one image.

What I want to do is to devide the image into severial small blocks in same size.

To do that, I wrote this tool function.

chop      :: Int -> [a] -> [[a]]
chop _ [] = []
chop n ls = take n ls : chop n (drop n ls)

But I do not know how to use it to write the function.

Thanks for any advice.

    Regards
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L.Guo
2007-06-13