[Haskell-cafe] Type infer

Marco Túlio Gontijo e Silva malebria at riseup.net
Thu Jan 25 07:57:14 EST 2007


Em Qua, 2007-01-24 às 20:36 -0500, Bryan Donlan escreveu:
> Marco Túlio Gontijo e Silva wrote:
> > Hello,
> > 
> > I'm trying to define a partition__ function that is like
> > Data.Set.partition, but use State Monad:
> > 
> >> import Data.Set
> >> import Control.Monad.State
> > 
> >> partition__ f =
> >>     do
> >>     snapshot <- get
> >>     let
> >>         (firsts, rest) = Set.partition f snapshot
> >>     put rest
> >>     return firsts
> > 
> > When I try to infer it's type in ghci I got:
> > 
> > $ ghci
> >    ___         ___ _
> >   / _ \ /\  /\/ __(_)
> >  / /_\// /_/ / /  | |      GHC Interactive, version 6.6, for Haskell 98.
> > / /_\\/ __  / /___| |      http://www.haskell.org/ghc/
> > \____/\/ /_/\____/|_|      Type :? for help.
> > 
> > Loading package base ... linking ... done.
> > Prelude> :load partition.hs
> > [1 of 1] Compiling Main             ( partition.hs, interpreted )
> > Ok, modules loaded: Main.
> > *Main> :type partition__
> > partition__ :: (MonadState (Set a) t, Ord a) => (a -> Bool) -> t (Set a)
> > 
> > Ok, then I add
> > 
> >> partition__ :: (MonadState (Set a) t, Ord a) => (a -> Bool) -> t (Set
> > a)
> > 
> > to the file and then:
> > 
> > *Main> :reload
> > [1 of 1] Compiling Main             ( partition.hs, interpreted )
> > 
> > partition.hs:4:0:
> >     Non type-variable argument in the constraint: MonadState (Set a) t
> >     (Use -fglasgow-exts to permit this)
> >     In the type signature for `partition__':
> >       partition__ :: (MonadState (Set a) t, Ord a) =>
> >                      (a -> Bool) -> t (Set a)
> > Failed, modules loaded: none.
> > 
> > Why do I need glasgow-exts to specify a type infered by GHCi without
> > -fglasgow-exts?
> 
> I'd imagine the check that you're using -fglasgow-exts is performed when 
> parsing type signatures from the parser. When you allow GHC to infer the 
> type, it's pulling that from Control.Monad.State, which was compiled 
> with -fglasgow-exts - it's simply not checking that all the types you 
> might infer from there are legal without -fglasgow-exts.

Makes sense, but isn't it a bug? It shouldn't be able infer types that
are not allowed without -fglasgow-exts, right?

Thanks.

-- 
malebria
Marco Túlio Gontijo e Silva
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