[Haskell-cafe] Composing functions with runST
Yitzchak Gale
gale at sefer.org
Mon Jan 1 06:02:13 EST 2007
Can anyone explain the following behavior (GHCi 6.6):
Prelude Control.Monad.ST> runST (return 42)
42
Prelude Control.Monad.ST> (runST . return) 42
<interactive>:1:9:
Couldn't match expected type `forall s. ST s a'
against inferred type `m a1'
In the second argument of `(.)', namely `return'
In the expression: (runST . return) 42
In the definition of `it': it = (runST . return) 42
Thanks,
Yitz
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