[Haskell-cafe] Re: Very fast loops. Now!
David Roundy
droundy at darcs.net
Mon Feb 12 17:04:29 EST 2007
On Tue, Feb 13, 2007 at 08:18:25AM +1100, Donald Bruce Stewart wrote:
> Now, if we rewrite it to not use the temporary:
>
> go :: Double -> Double -> Int -> IO ()
> go !x !y !i
> | i == 1000000000 = printf "%.6f\n" (x+y)
> | otherwise = go (x*y/3) (x*9) (i+1)
>
>
> for (; i<1000000000; i++) {
> x = x*y/3.0;
> y = x*9.0;
> }
>
> ------------------------------------------------------------------------
>
> $ time ./hp
> 3.333333
> ./hp 9.95s user 0.00s system 99% cpu 9.965 total
>
> $ time ./cc
> 3.333333
> ./cc 10.06s user 0.00s system 99% cpu 10.110 total
I'm rather curious (if you're sill interested) how this'll be affected by
the removal of the division from the inner loop. e.g.
go :: Double -> Double -> Int -> IO ()
go !x !y !i
| i == 1000000000 = printf "%.6f\n" (x+y)
| otherwise = go (x*y*(1.0/3)) (x*9) (i+1)
for (; i<1000000000; i++) {
x = x*y*(1.0/3.0);
y = x*9.0;
}
My guess is that the code will be far faster, and that the differences
between C and Haskell will therefore be more pronounced. After all,
division is a slow operation...
--
David Roundy
Department of Physics
Oregon State University
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