lrpalmer at gmail.com
Thu Dec 6 02:10:45 EST 2007
Oops, not quite. "otherwise ==" should be "otherwise =". Looks like
you already go this from the first one, but guard syntax looks like:
| cond1 = ...
| cond2 = ...
| otherwise = ...
(otherwise is not actually necessary; it is just a synonym for True)
On Dec 6, 2007 7:09 AM, Luke Palmer <lrpalmer at gmail.com> wrote:
> Just remove that if. What comes after | is already a conditional.
> On Dec 6, 2007 7:03 AM, Ryan Bloor <ryanbloor at hotmail.com> wrote:
> > hi
> > I have a matching problem... I am wanting to identify whether or not a
> > string is an opening substring of another (ignoring leading spaces). I have
> > this:
> > word is a single word and str is a string.
> > match :: String -> String -> (Bool, String)
> > match word str
> > | if removeSpace str `elem` (removeSpace word) ++ rest =
> > (True, rest)
> > | otherwise == (False,str)
> > where rest = str
> > Any help?
> > Ryan
> > ________________________________
> > Can you guess the film? Search Charades!
> > _______________________________________________
> > Haskell-Cafe mailing list
> > Haskell-Cafe at haskell.org
> > http://www.haskell.org/mailman/listinfo/haskell-cafe
More information about the Haskell-Cafe