[Haskell-cafe] matching

[Luke Palmer]

Oops, not quite.  "otherwise ==" should be "otherwise =".  Looks like
you already go this from the first one, but guard syntax looks like:

defn
  | cond1 = ...
  | cond2 = ...
  | ...
  | otherwise = ...

(otherwise is not actually necessary; it is just a synonym for True)

Luke

On Dec 6, 2007 7:09 AM, Luke Palmer <lrpalmer at gmail.com> wrote:
> Just remove that if.  What comes after | is already a conditional.
>
> Luke
>
>
> On Dec 6, 2007 7:03 AM, Ryan Bloor <ryanbloor at hotmail.com> wrote:
> >
> > hi
> >
> >  I have a matching problem... I am wanting to identify whether or not a
> > string is an opening substring of another (ignoring leading spaces). I have
> > this:
> >  word is a single word and str is a string.
> >
> >  match :: String -> String -> (Bool, String)
> > match word str
> >                   | if removeSpace str `elem` (removeSpace word) ++ rest =
> > (True, rest)
> >                   | otherwise == (False,str)
> >                       where rest = str
> >
> >  Any help?
> >
> >  Ryan
> >
> >
> >
> >
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>