[Haskell-cafe] distinguish functions from non-functions in a
ryani.spam at gmail.com
Wed Dec 5 17:21:07 EST 2007
No, that doesn't work; it's close, but not quite. liftM doesn't have the
right type signature.
liftM :: Monad m => (a -> r) -> (m a1 -> m r)
What would work is if you could define a function
liftLast :: Monad m => (a0 -> a1 -> ... -> aN -> r) -> (a0 -> a1 -> ... ->
aN -> m r)
nary' f = runIdentity . nary (liftLast f)
On 12/5/07, Dan Weston <westondan at imageworks.com> wrote:
> Wouldn't any isomorphism do (like the Identity monad)? How about
> nary' f = runIdentity . nary (liftM f) . return
> Brandon S. Allbery KF8NH wrote:
> > On Dec 5, 2007, at 16:00 , Philipp N. wrote:
> >> the odd thing is. you can get this to work, if you have a terminating
> >> type
> >> as result type (for example (IO x)). then you can work with all types
> >> x), (a -> IO x), (a -> b -> IO x), ...
> >> but i don't want this delimiter IO! any ideas?
> > Use ST instead? (just tossing ideas in the wind...)
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