[Haskell-cafe] foild function for expressions
thrakatak at hotmail.com
Tue Dec 4 12:19:55 EST 2007
Brent Yorgey wrote:
> One comment: it looks like (add exp1 exp2), (and exp1 exp2) and so on
> are not correct. The second argument of foldExp is a value of type Exp,
> you are pattern-matching on the constructors of Exp, and constructors are
> always uppercase. Perhaps Exp has constructors named Add, And, and so on?
> Then you would want to do something like
Yepp, it's my fault I wasn't too precise in my explanation.
There's a declaration of the data type EXP, which is not difficult to gess
with the things I've said:
data Exp = LitI Int
|Add Exp Exp
|And Exp Exp
|If Exp Exp Exp
I'm going to read carefully all of your answer now (thanks to all!!!), and
then I'll tell you. ;)
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