[Haskell-cafe] foild function for expressions

[Carlo Vivari]

Brent Yorgey wrote:
> 
> 
> One comment: it looks like (add exp1 exp2), (and exp1 exp2) and so on
> above
> are not correct.  The second argument of foldExp is a value of type Exp,
> so
> you are pattern-matching on the constructors of Exp, and constructors are
> always uppercase.  Perhaps Exp has constructors named Add, And, and so on?
> Then you would want to do something like
> 
> 

Yepp, it's my fault I wasn't too precise in my explanation.
There's a declaration of the data type EXP,  which is not difficult to gess
with the things I've said:

data Exp = LitI Int
               |LitB Bool
               |Add Exp Exp
               |And Exp Exp
               |If Exp Exp Exp

I'm going to read carefully all of your answer now (thanks to all!!!), and
then I'll tell you. ;)


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