[Haskell-cafe] GHC optimisations
Donald Bruce Stewart
dons at cse.unsw.edu.au
Tue Aug 21 07:57:29 EDT 2007
phil:
> On Mon, Aug 20, 2007 at 09:57:38PM +0100, Simon Peyton-Jones wrote:
> >GHC does some constant folding, but little by way of strength
> >reduction, or using shifts instead of multiplication. It's pretty
> >easy to add more: it's all done in a single module. Look at
> >primOpRules in the module PrelRules.
> >
> >Patches welcome! But please also supply test-suite tests that check
> >the correctness of the rules.
>
> Sucking another example out of comp.lang.functional:
>
> This:
>
> import System
>
> f :: Int -> Int -> Int
> f s n = if n > 0 then f (s+n) (n-1) else s
>
> main = do
> [n] <- getArgs
> putStrLn $ show $ f 0 (read n)
>
> is 3-4x slower than this:
>
> #include <stdio.h>
> #include <stdlib.h>
> #include <assert.h>
>
> int f(int s, int n) {
> return n > 0 ? f(s+n, n-1) : s;
> }
>
> int main(int argc, char *argv[]) {
> assert(argc == 2);
> printf("%d\n", f(0, strtol(argv[1],0,0)));
> }
>
> The generated assembler suggests (if I've read it correctly) that gcc
> is spotting that it can replace the tail call with a jump in the C
> version, but for some reason it can't spot it for the Haskell version
> when compiling with -fvia-C (and neither does ghc itself using
> -fasm). So the haskell version ends up pushing and popping values on
> and off the stack for every call to f, which is a bit sad.
>
That doesn't sound quite right. The C version should get a tail call ,
with gcc -O2, the Haskell version should be a tail call anyway.
Let's see:
C
$ gcc -O t.c -o t
$ time ./t 1000000000
zsh: segmentation fault (core dumped) ./t 1000000000
./t 1000000000 0.02s user 0.22s system 5% cpu 4.640 total
Turning on -O2
$ time ./t 1000000000
-243309312
./t 1000000000 1.89s user 0.00s system 97% cpu 1.940 total
And GHC:
$ ghc -O2 A.hs -o A
$ time ./A 1000000000
-243309312
./A 1000000000 3.21s user 0.01s system 97% cpu 3.289 total
So, what, 1.6x slower than gcc -O2
Seems ok without any tuning.
-- Don
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