[Haskell-cafe] monad subexpressions
Simon Peyton-Jones
simonpj at microsoft.com
Fri Aug 3 12:29:15 EDT 2007
| f (g (<- mx))
|
| does this stand for
|
| (a) mx >>= \x-> f (g x)
| (b) f (mx >>= \x-> (g x))
| (c) none of the above, because there's no do
| (d) something else entirely
For me the answer is definitely (c). Furthermore there must be no lambda between the "monadic splice" and the "do".
Given that, I think the meaning of a monadic splice is straightforward, and all your excellent questions have easy answers. The question remains of whether or not it's valuable.
Simon
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